python-pycurl 7.43.0.3

Name python-pycurl
Version 7.43.0.3
Summary A Python Interface To The cURL library
Description PycURL is a Python interface to libcurl, the multiprotocol file transfer library. Similarly to the urllib Python module, PycURL can be used to fetch objects identified by a URL from a Python program
Section devel/python
License LGPL-2.0-only | MIT
Homepage http://pycurl.io/
Recipe file recipes-devtools/python/python-pycurl_7.43.0.3.bb
Layer meta-python2 (kirkstone branch)
Inherits
  • distutils
  • distutils-base
  • pypi
  • python-dir
  • pythonnative
  • setuptools
Dependencies
  • curl
  • python
  • python-native
  • virtual/i686-oe-linux-compilerlibs
  • virtual/i686-oe-linux-gcc
  • virtual/libc
PACKAGECONFIG options

Sources

https://files.pythonhosted.org/packages/source/p/pycurl/pycurl-7.43.0.3.tar.gz

Patches

None

Other branches

This recipe in other branches of meta-python2:

Branch Recipe
master python-pycurl 7.43.0.3
kirkstone (Yocto Project 4.0) python-pycurl 7.43.0.3 (this recipe)
honister (Yocto Project 3.4) python-pycurl 7.43.0.3
hardknott (Yocto Project 3.3) python-pycurl 7.43.0.3
gatesgarth (Yocto Project 3.2) python-pycurl 7.43.0.3
dunfell (Yocto Project 3.1) python-pycurl 7.43.0.3
zeus (Yocto Project 3.0) python-pycurl 7.43.0.3